In this Method we will learn how to find a square of any two digit number in a very short span of time.
In this we will use our basic formula but in a different way.
For Ex. (41)2
For Ex. (67)2
Problems For Practice
Take a look at the fomula for finding a square.
(a + b)2 = a2 + 2ab + b2
➤ Divide the result portion into 3 parts. Consider Tens place digit as ‘a’ and Unit place digit as ‘b’ as shown.
➤ In leftmost part we will calculate a2 , in the rightmost part we will calculate b2 and in the middle part we will calculate product of 2ab.
➤ If any of the parts whether it is middle or rightmost or both contain two digit number we will simply take carry their tens digits.
For Ex. (41)2
Step 1 :- We will consider '4' as 'a' and '1' as 'b'
and we will calculate
a2 = (4)2 =16
2ab = 2 * 4 * 1 = 8
b2 = (1)2 =1
Step 2 :- As we can see middle part and rightmost part do not contain two digit number they will be taken as it is in the Final result.
Final Result :- 1681
For Ex. (67)2
Step 1 :- We will consider '6' as 'a' and '7' as 'b'
and we will calculate
a2 = (6)2 =36
2ab = 2 * 6 * 7 = 84
b2 = (7)2 =49
Step 2 :- As we can see middle part and rightmost part both contain two digit numbers they will be taken carry as shown.
Final Result :- 4489.For Ex. (72)2
Step 1 :- We will consider '7' as 'a' and '2' as 'b'
and we will calculate
a2 = (7)2 =49
2ab = 2 * 7 * 2 = 28
b2 = (2)2 =4
Step 2 :- As we can see only middle part contains two digit number 2 will be taken carry as shown.
Final Result :- 5184.
Problems For Practice
1) (34)2
2) (57)2
3) (49)2
4) (63)2
5) (14)2
6) (24)2
7) (77)2
8) (58)2
9) (94)2
10) (87)2
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